3.2x^2+0.2x=5

Solution for 3.2x^2+0.2x=5 equation:

3.2x^2+0.2x=5

We move all terms to the left:

3.2x^2+0.2x-(5)=0

a = 3.2; b = 0.2; c = -5;
Δ = b2-4ac
Δ = 0.22-4·3.2·(-5)
Δ = 64.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.2)-\sqrt{64.04}}{2*3.2}=\frac{-0.2-\sqrt{64.04}}{6.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.2)+\sqrt{64.04}}{2*3.2}=\frac{-0.2+\sqrt{64.04}}{6.4}
$